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冀教版数学二年级下册第二单元第四课时
有余数除法的应用试卷
一、填空我最棒
1.除法算式17÷4=4……1,读作:( ),其中17叫做( ),第一个4叫做( ),第二个是4叫做( ),1叫做( )。21世纪教育网版权所有
2.在计算有余数的除法时,计算的结果,( )要比( )小。
3.一个数除以6,如果有余数,余数可能有( )个,其中最大的余数是( )。
4. 19个☆,每5个分一份,可以分( )份,还余( )个。 9个△,平均分成2份,每份有( )个,还剩( )个。。21教育网
二、连一连
12÷8= 58÷7= 59÷8= 66÷8= 39÷4=
三、开火车
四、看图填算式
1.
□÷□=□……□
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□÷□=□……□
五、想一想,填一填
1.( )÷( )=( )……6 除数最小是( )
2.( )÷9=( )……( ) 余数最大是( )
六、解决问题
1.小明要把13本卡通书分给4个小朋友,算一算每个小朋友平均可以分得几本?还剩几本?
2.一件上衣要钉5颗扣子。有41颗扣子,可以钉几件上衣,还剩几颗?
3.
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(1)小明有23元钱,最多可以买几副手套?
(2)小芳的钱可以买4顶帽子还多1元钱,你知道小芳有多少钱吗?
答案:
一、填空我最棒
1.17除以4等于4余1;被除数;除数;商;余数.
2.余数;除数.
3.5;5.
4.3;4;4;1.
二、连一连
12÷8= 58÷7= 59÷8= 66÷8= 39÷4=
三、开火车
四、看图填算式
1.21÷6=3……3
2.19÷5=3……4
五、想一想,填一填
1.( )÷( )=( )……6 除数最小是( 7 )
2.( )÷9=( )……( ) 余数最大是( 8 )
六、解决问题
1.13÷4=3(本)……1(本)
答:每个小朋友平均分得3本,还剩1本。
2.41÷5=8(件)……1(颗)
答:可以钉8件上衣,还剩1颗。
余数是2
余数是3
余数是4
76÷8=
47÷9=
82÷9=
31÷5=
57÷6=
22÷8=
余数是2
余数是3
余数是4
47÷9=5……2
82÷9=9……1
31÷5=6……1
57÷6=9……3
22÷8=2……6
76÷8=9……4
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