2020-2021年度浙教版七年级数学下册《3.2单项式的乘法》同步提升训练(附答案)
1.计算﹣m2n?(﹣mn3)的结果是( )
A.m4n3 B.m3n3 C.﹣m3n4 D.m3n4
2.下列计算正确的是( )
A.3x3?2x2y=6x5 B.2a2?3a3=6a5
C.(﹣2x)?(﹣5x2y)=﹣10x3y D.(﹣2xy)?(﹣3x2y)=6x3y
3.若单项式﹣8xay和x2yb的积为﹣2x5y6,则ab的值为( )
A.2 B.30 C.﹣15 D.15
4.计算(﹣x)?(﹣2x2)(﹣4x4)的结果为( )
A.﹣4x6 B.﹣4x7 C.4x8 D.﹣4x8
5.长方形的长为3x2y,宽为2xy3,则它的面积为( )
A.5x3y4 B.6x2y3 C.6x3y4 D.
6.计算(﹣ab)3?a2b4的结果正确的是( )
A.a5b6 B.﹣a5b6 C.a5b7 D.﹣a5b7
7.计算(m3n)2?(﹣mn)2的结果是( )
A.m7n4 B.﹣m7n4 C.m8n4 D.﹣m8n4
8.计算2x?(﹣3xy)2?(﹣x2y)3的结果是( )
A.18x8y5 B.6x9y5 C.﹣18x9y5 D.﹣6x4y5
9.计算:(﹣2ab2)?(﹣3a2)= .
10.计算(﹣2a)3(﹣3a)2= .
11.计算(﹣8ab)?(a2b)= .
12.计算
(﹣b)2?(﹣b)3?(﹣b)5= ;(﹣x2)?(﹣x)2?(﹣x)3= ;
﹣4xy3?(﹣xy)+(﹣3xy2)2= .
13.用科学记数法表示计算结果:(3.5×103)×(﹣4×105)= .
14.计算:(﹣3xy)2?(﹣x2z)= .
15.计算:x4?2(﹣x2)?(﹣x)2?[﹣(﹣x2)3]4?2(﹣x)2的值为 .
16.计算:(﹣x2y)3(﹣3xy2)2= .
17.若ab3=﹣2,则(﹣3ab)?2ab5= .
18.计算:= .
19.计算:a3b2?(﹣b2)2+(﹣2ab2)3.
20.计算:
(1)x?x3+x2?x2. (2)5x2y?(﹣2xy2)3.
(3)7x4?x5?(﹣x)7+5(x4)4.
21.2x3?(﹣x)5﹣x5?(﹣x)3.
22.计算:m4n2+2m2?m4+(m2)3﹣(m2n)2
23.化简(5x)2?x7﹣(3x3)3+2(x3)2+x3
24.(﹣2y3)2+(﹣4y2)3﹣(﹣2y)2?(﹣3y2)2.
25.计算
(1)(﹣2xy2)6+(﹣3x2y4)3;
(2)﹣x2?(﹣x)3+3x3(﹣x)2﹣4(﹣x)?(﹣x4).
参考答案
1.解:原式=m3n4,
故选:D.
2.解:A、3x3×2x2y=6x5y,故此选项错误;
B、2a2×3a3=6a5,故此选项正确;
C、(﹣2x)×(﹣5x2y)=10x3y,故此选项错误;
D、(﹣2xy)×(﹣3x2y)=6x3y2,故此选错误.
故选:B.
3.解:﹣8xay×x2yb=﹣2xa+2yb+1=﹣2x5y6,
∴a+2=5,b+1=6,
解得a=3,b=5,
∴ab=3×5=15,
故选:D.
4.解:(﹣x)?(﹣2x2)(﹣4x4)=﹣4x7,
故选:B.
5.解:3x2y?2xy3=6x3y4,
故选:C.
6.解:(﹣ab)3?a2b4=﹣a3b3?a2b4=﹣a5b7,
故选:D.
7.解:(m3n)2?(﹣mn)2=m6n2?m2n2=m8n4.
故选:C.
8.解:2x?(﹣3xy)2?(﹣x2y)3=2x?9x2y2?(﹣x6y3)=﹣18x9y5;
故选:C.
9.解:(﹣2ab2)?(﹣3a2)=6a3b2.
故答案为:6a3b2.
10.解:原式=﹣8a3?9a2=﹣72a5.
11.解:(﹣8ab)?(a2b)=(﹣8×)?(a?a2)?(b?b)=﹣6a3b2,
故答案为:﹣6a3b2.
12.解:(﹣b)2?(﹣b)3?(﹣b)5=(﹣b)10=b10;
(﹣x2)?(﹣x)2?(﹣x)3=﹣x2?x2?(﹣x3)=x7;
﹣4xy3?(﹣xy)+(﹣3xy2)2=4x2y4+9x2y4=13x2y4.
故答案为:b10;x7;13x2y4.
13.解:(3.5×103)×(﹣4×105)=﹣14×108=﹣1.4×109.
故答案为:﹣1.4×109.
14.解:原式=9x2y2?(﹣x2z)=﹣9x4y2z,
故答案为:﹣9x4y2z.
15.解:x4?2(﹣x2)?(﹣x)2?[﹣(﹣x2)3]4?2(﹣x)2
=x4?(﹣2x2)?x2?x24?2x2=﹣4x4+2+2+24+2=﹣4x34,
故答案为:﹣4x34.
16.解:(﹣x2y)3(﹣3xy2)2=(﹣x6y3)×(9x2y4)=﹣x8y7.
故答案为:﹣x8y7.
17.解:∵ab3=﹣2,
∴(﹣3ab)?2ab5=﹣6a2b6=﹣6(ab3)2=﹣6×(﹣2)2=﹣24,
故答案为:﹣24.
18.解:原式=x2ny2?4xy2=x2n+1y4.
故答案为:x2n+1y4.
19.解:a3b2?(﹣b2)2+(﹣2ab2)3=a3b2?b4﹣8a3b6=a3b6﹣8a3b6=﹣7a3b6.
20.解:(1)原式=x4+x4=2x4;
(2)原式=5x2y?(﹣8x3y6)=﹣40x5y7;
(3)原式=7x4?x5?(﹣x7)+5x16=﹣7x16+5x16=﹣2x16.
21.解:2x3?(﹣x)5﹣x5?(﹣x)3=﹣2x8+x8,=﹣x8.
22.解:原式=m4n2+2m6+m6﹣m4n2,=3m6.
23.解:(5x)2?x7﹣(3x3)3+2(x3)2+x3=25x2?x7﹣27x9+2x6+x3
=25x9﹣27x9+2x6+x3=﹣2x9+2x6+x3.
24.解:(﹣2y3)2+(﹣4y2)3﹣(﹣2y)2?(﹣3y2)2
=4y6﹣64y6﹣4y2?(9y4)=4y6﹣64y6﹣36y6=﹣96y6.
25.解:(1)(﹣2xy2)6+(﹣3x2y4)3=64x6y12﹣27x6y12=37x6y12;
(2)﹣x2?(﹣x)3+3x3(﹣x)2﹣4(﹣x)?(﹣x4)=x5+3x5﹣4x5=0.